Ответы на вопрос:
6;-11/5
Объяснение:
7/(x+1)+(x+4)/(2x-2)=(3x^2-38)/(x^2-1)
x≠-1
(x^2+19x-10)/(2(x-1)(x+1))=(3x^2-38)/((x-1)(x+1))
x^2+19x-10=2(3x^2-38)
-5x^2+19x+66=0
-(x-6)(5x+11)=0
(x-6)(5x+11)=0
x-6=0 or 5x+11=0
x=6 or x=-11/5
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