Ответы на вопрос:
X=π/2-y sin(π/2-2y)=2sin(π/2-y)*cosy -cos2y=2cos²y 2cos²у+cos2y=0 2cos²у+2cos²у-1=0 4cos²у=1 cos²у=1/4 cosу=1/2 или cosу=-1/2 для cosy=1/2 y1=π/3+2πn, n € z y2=-π/3+2πn, n € z для cos y=-1/2 y3=2π/3+2πn, n € z y4=-2π/3+2πn, n € z x1=π/2-π/3+2πn=π/6+2πn, n € z x2=π/2+π/3+2πn=5π/6+2πn, n € z x3=π/2-2π/3+2πn=-π/6+2πn, n € z x4=π/2+2π/3+2πn=7π/6+2πn, n € z
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