Ответы на вопрос:
а.)(x-3)*(x-4)>0
0\\D=(-7)^{2} -4*12=49-48=1\\x_{1}=\frac{7+1}{2}=4\\x_{2}=\frac{7-1}{2}=3\\" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-7x%2B12%3E0%5C%5CD%3D%28-7%29%5E%7B2%7D%20-4%2A12%3D49-48%3D1%5C%5Cx_%7B1%7D%3D%5Cfrac%7B7%2B1%7D%7B2%7D%3D4%5C%5Cx_%7B2%7D%3D%5Cfrac%7B7-1%7D%7B2%7D%3D3%5C%5C" title="x^{2} -7x+12>0\\D=(-7)^{2} -4*12=49-48=1\\x_{1}=\frac{7+1}{2}=4\\x_{2}=\frac{7-1}{2}=3\\">
x∪[3;4]
б.)(x-3)*(x-4)<0
x∪[-∞;3];[4;∞]
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