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15.07.2021 20:25
Химия
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DiModDi
DiModDi
4,5(93 оценок)

mgo+2нсl=mgcl2+h2o

находим число молей оксида магния:

n (mgo)=4/40=0,1 моль

по уравнению реакции n (mgo) = n (mgcl2).

найдем массу образовавшейся соли, т.е. массу хлорида магния:

m (mgcl2)=0,1*95=9,5 г.

ответ: m (mgcl2) = 9,5 г.

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