Ответы на вопрос:
1) x² + 10x + 24 = 0
a = 1, b = 10, c = 24
d = b² - 4ac = 10² - 4*1*24 = 100 - 96 = 4
√d = √4 = 2
x1 = (-b + √d)/2a = (-10 + 2)/2 = -8/2 = -4
x2 = (-b - √d)/2a = (-10 -2)/2 = -12/2 = -6
ответ: -4; -6
2) x² - 5x - 24 = 0
a = 1, b = -5, c = -24
d = b² - 4ac= (-5)² - 4*1*(-24) = 25 + 96 = 121
√d = √121 = 11
x1 = (-b + √d)/2a = (5 + 11)/2 = 16/2 = 8
x2 = (-b - √d)/2a = (5 - 11)/2 = -6/2 = -3
ответ: 8; -3
3) 40x² + 50x + 10 = 0
a = 40, b = 50, c = 10
d = b² - 4ac= 50² - 4*40*10 = 2500 - 1600 = 900
√d = √900 = 30
x1 = (-b + √d)/2a = (-50 + 30)/2*40 = -20/80 = -0.25
x2 = (-b - √d)/2a = (-50 - 30)/2*40 = -80/80 = -1
ответ: -0.25; -1
Популярно: Алгебра
-
Alphons14521.01.2023 20:04
-
nikitosgurbano09.07.2020 10:43
-
bukshtanovich2025.05.2022 15:27
-
lord5002.01.2020 22:57
-
Dood86ft2435465709.05.2022 07:22
-
omim18.08.2020 04:54
-
ale200517111218.08.2020 20:50
-
zhanbolat200726.06.2020 21:55
-
shlyakhovdaniik01.01.2021 20:32
-
AlexanderVard15.08.2021 16:30