Ответы на вопрос:
Решение 1) 2sin^2x - sinx - 1=0 d = 1 + 4*2*1 = 25 a) sinx = (1-3)/4 sinx = -1/2 x = (-1)^n*arcsin(-1/2) + πn, n∈z x = (1)^(n+1)*arcsin(1/2) + πn, n∈z x1 = (1)^(n+1*(π/6) + πn, n∈z b) sinx = (1+3)/4 sinx = 1 x2 = π/2 + 2πk,k ∈z ответ: x1 = (1)^(n+1)*(π/6) + πn, n∈z; x2 = π/2 + 2πk,k ∈z 2tg^2x + 3tgx - 2=0 d = 9 + 4*2*2 = 25 a) tgx = (-3 -5)/4 tgx = -2 x1 = arctg(-2) + πn, n∈z x1 = - arctg(2) + πn, n∈z b) tgx = (-3+5)/4 tgx = 1/2 x2 = arctg(1/2) + πk, k∈z ответ: x1 = - arctg(2) + πn, n∈z; x2 = arctg(1/2) + πk, k∈z.
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