Ответы на вопрос:
дано
w(fe2o3) = 80%
η(fe) = 0.9
mтехн(fe2o3) = 1 kg = 1000 g
m(
m чист (fe2o3) = 1000 * 80% / 100% = 800 g
fe2o3+3co--> 2fe+3co2
m(fe2o3) = 160 g/mol
n(fe2o3) = m/m = 800/ 160 = 5 mol
n(fe2o3) = 3n(fe)
n(fe) = 3*5 = 15 mol
m(fe) = 56 g/mol
mтеор (fe) = n*m = 15*56 = 840 g
m(практ fe) = 840 * 0.9= 756 g
ответ 756 г
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