Ответы на вопрос:
2cos^2 5x - sin 5x cos 5x - sin^2 5x = 0 | : сos² 5x≠ 0 2 - tg 5x - tg² 5x = 0 tg5x = t t² + t - 2 = 0 по т. виета корни -1 и 2 а) t = -1 б) t = -2 tg5x = -1 tg5x = -2 5x = -π/4 + πk , ∈z 5x = arctg(-2) + πn , n ∈z x = -π/20 + πk/5 , k ∈z x = -1/5*arctg2 + nπ/5 , n ∈z
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