Ответы на вопрос:
F(x) = x² + 3x - 1 f '(x) = (x²)' + 3(x)' - 1' = 2x + 3 f(x) = x³(4 + 2x - x²) = 4x³ + 2x⁴ - x⁵ f '(x) = 4(x³)' + 2(x⁴)' - (x⁵)' = 12x² + 8x³ - 5x⁴ f(x) = x²(3x + x³) = 3x⁴ + x⁵ f '(x) = 3(x⁴)' + (x⁵)' = 12x³ + 5x⁴ f(x) = x² - 3x f '(x) = (x²)' - 3(x)' = 2x - 3 f '(1/2) = 2 * 1/2 - 3 = - 2 f '(2) = 2 * 2 - 3 = 1
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