Ответы на вопрос:
1) a^2+64–8a=a^2–2*a*4+4^2+48=(a–4)^2+48 2) 121–b^2=(11–b)(11+b) 3) (x–3)/(9–x^2)=–(3–x)/((3–x)(3+x))=–1/(3+x) 4) (a–5)(a+2)–a(a–7)=a^2+2a–5a–10–a^2+7a=4a–10=2(2a–5) 5) (6–x–x^2)/(x–2) 6–x–x^2=0 x^2+x–6=0 по теореме виета имеем x1+x2= –p x1+x2= –1 x1= –3 x1*x2=q x1*x2= –6 x2= 2 6–x–x^2=0 –x^2–x+6= –(x+3)(x–2) (6–x–x^2)/(x–2) = –(x+3)(x–2) / (x–2) = – (x+3) = –x–3
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