Ответы на вопрос:
-2+3b-4b-b-1=-2b-3
Объяснение:
-2+3b-4b-b-1=(3b-4b-b)+(-2+(-1))=(3-4-1)b-(2+1)=-2b-3
U= arccos (- 4/5) v = arcsin 1/3 sin(u + v) = sin(arccos (- 4/(arcsin 1/3) + cos(arccos (- 4/(arcsin (1/3)) = = √[1 – (- 4/5)²] * √[1 – (1/3)²] + (- 4/5)*(1/3) = √[1 – 16/25] * √[1 – 1/9] - 4/15 = = √[(9/25)*(8/9)] – 4/15 = (2√2) / 5 - 4/15 = (6√2 - 4) / 15
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