Ответы на вопрос:
Log0,2(x-10) - log0,2(x+2)> =-1 одз: {x-10> 0; x> 10 {x+2> 0; x> -2 x e (10; +беск.) log0,2[(x-10)/(x+2)] > =log0,2(5) (x-10)/(x+2) < =5 (x-10)/(x+2) - 5< =0 [(x-10)-5(x+2)]/(x+2)< =0 (x-10-5x-10)/(x+2)< =0 (-4x-20)/(x+2)< =0 (4x+20)/(x+2)> =0 [4(x+5)]/(x+2)> =0 +-+ /////////////////////////////// //////////////////////////// с учетом одз ответ: (10; +беск.)
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