Ответы на вопрос:
T1=20 °с, r1= 55 ом, r2= 600 ом, α=0,0048. t2-? r2=r1(1+α(t-t1)); 1+α(t-t1)=r2/r1; α(t-t1)=r2/r1-1; α(t-t1)=(r2-r1)/r1; t-t1= (r2-r1)/(αr1). t= (r2-r1)/(αr1)+t1; t=545/(0,0048*55)+20=2084 °.
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