Ответы на вопрос:
Решение sin^6(a)+cos⁶(a) = (sin²a)³ + (cos²a)³ = (sin²a + cos²a)*(sin⁴a - sin²acos²a + cos⁴a) = = [(sin⁴a + 2sin²acos²a + cos⁴a) - 3sin²acos²a] = (sin²a + cos²a)² - 3sin ²acos²a = = 1 - 3sin²acos²a = 1 - (3/4)*(2sinacosa)*( 2sinacosa) == 1 - (3/4)*(sin²2a) = 1 - [(1 - cos4a)/2] = = 1 - 3/8 + (3/8)*cos4a = 5/8 + (3/8)*cos4a = (1/8)*(3cos4a + 5)
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