Даны вершины треугольника a(1,7), b(3,-11), с(11,-3) состалить ураапения высоты и биссектрисы треугольника , проведённых из точки c

157

246

Посмотреть ответы 1

Ответы на вопрос:

lour1

Геометрия

4,6(16 оценок)

А) ak/kb = 2 ; bm/mc = 1/3, co/ok - ? ; ao/om - ? ak/ab * bm/mc * co/ok = 1 2/3 * 1/3 * co/ok = 1 2/9 * co/ok = 1 co/ok = p = 9/2 bk/ak * mc/bc * ao/om = 1 1/2 * 3/4 * ao/om =1 3/8 * ao/om = 1 ao/om = l = 8/3 б) ak/kb = 2/3 ; bm/mc = 1/2, co/ok - ? ; ao/om - ? ak/ab * bm/mc * co/ok = 12/5 * 1/2 * co/ok = 1 1/5 * co/ok = 1 co/ok = p = 5 bk/ak * mc/bc * ao/om = 13/2 * 2/3 * ao/om = 1 ao/om = l = 1 в) ak/kb = 3 ; co/ok = 2 ; bm/mc - ? , ao/om - ? ak/ab * co/ok * bm/mc = 1 3/4 * 2/1 * bm/mc =13/2 * bm/mc =1 bm/mc = m = 2/3 bk/ak * mc/bc * ao/om = 11/3 * 3/5 * ao/om = 1 1/5 * ao/om = 1 ao/om = l = 5 г) ak/kb = 2 ; ao/om = 3 ; co/ok - ? ; bm/mc - ? am/ao * ab/ak * bm/mc = 1 4/3 * 3/2 * bm/mc = 12 * bm/mc = 1 bm/mc = m = 1/2 ak/ab * bm/mc * co/ok = 1 2/3 * 1/2 * co/ok = 1 1/3 * co/ok = 1 co/ok = p = 3 д) bm/mc = 1/3 ; ao/om = 1/3; ak/bk - ? ; co/ok - ? om/oa * bc/mc * ak/bk = 1 3/1 * 4/3 * ak/bk = 1 4*ak/bk = 1 ak/bk = k = 1/4 ak/ab * bm/mc * co/ok = 1 1/5 * 1/3 * co/ok = 11/15 * co/ok =1 co/ok = p = 15 е) co/ok = 2 ; ao/om = 1; ak/kb - ? ; bm/mc - ? ck/ok * ao/om * ak/kb = 1 3/1 * 1/1 * ak/kb = 13 * ak/kb = 1 ak/kb = k = 1/3ak/ab * co/ok * bm/mc = 11/4 * 2/1 * bm/mc = 11/2 * bm/mc =1 bm/mc = m = 2