Ответы на вопрос:
F₁ = fcosα - fтр = fcosα - (mg-fsinα)*μ = =100*(√2/2) - (10*9.81 - 100*(√2/2))*0,1 = 70,7107 -2,7389 = 67,9717 h. a₁ = f₁ / m = 67,9717 / 10 = 6,79717 м/с². s₁ = a₁t₁^2 / 2 = 6,79717 *1² / 2 = 3.3986 м. f₂ = fтр₂ = -mgμ = -10*9,81*0,1 = -9,81 h a₂ = f₂ / m = -9,81 / 10 = -0,981 м/с². s₂ = v₁^2 / 2a₂ = 6,79717² / 2* -0,981 = 23,5482м s₁ + s₂ = 26,9468 м.
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