Ответы на вопрос:
3t^2 + 7t + 4 = 0 d = 49 - 4*4*3 = 1 t1 = ( - 7 +1)/6 = - 6/6 = - 1; t2 = ( - 7 - 1)/6 = - 4/3 = - 1 целая 1/3
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