Ответы на вопрос:
1. y=log₂(2x+3) 2.y=1/3cos(3x-π/2)-π³-e², x₀=π/3 y'=1/3 (-sin(3x-π/2))*3=-sin(3x-π/2) y'(x₀)=-sin(3*π/3-π/2)=-sin(π-π/2)=-sin(π/2)=-1 3. y=x², x₀=0,25 y'=2x k=y'(x₀)=2*0,25=0,5 4. sin(π/6-3x)-1/2=0 sin(π/6-3x)=1/2 π/6-3x=π/2+2πn 3x=π/6-π/2+2πn=π/6-3π/6+2πn=-2π/6+2πn=-π/3+2πn x=-π/9+2πn/3 , n∈z
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