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05.11.2022 09:05
Химия
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pavelshilov200oxnuw1
pavelshilov200oxnuw1
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А)n(h2)=1,5 моль     n=na*n=1,5*6*10²³=9*10²³ б)m(h2)=7 г     n=m/m=7г/2г/моль=3,5 моль     n=6*10²³*3,5 моль=21*10²³ в)n(h2)=4 кмоль=4000 моль     n=4000*6*10²³=24000*10²³

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