Ответы на вопрос:
1) (sinα/2 + cosα/2)²/(1 + sinα) = (sin²α/2 + 2sinα/2·cosα/2 + cos²α/2)/(1 + sinα) = (1 + sinα)/(1 + sinα) = 1.
2) (2sinα - sin2α)/(2sinα + sin2α) = (2sinα - 2sinαcosα)/(2sinα + 2sinαcosα) = 2sinα(1 - cosα)/2sinα(1 + cosα) = (1 - cosα)/(1 + cosα) = (2sin²α/2)/(2cos²α/2) = tg²α/2
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