Дано n(nh2 ch2 cooh)=1.2 моль m (naoh) =200 грам w(naoh)= 0,4 знайти m((nh2ch2coona)
100
178
Ответы на вопрос:
дано
m(ppa ch3cooh) = 64 g
w(ch3cooh) = 60%
m(ch3oh) = 32 g
m(
m(ch3cooh) = 64*60% / 100% = 38.4 g
m(ch3cooh) = 60 g/mol
n(ch3cooh) = m/m = 38.4 / 60 = 0.64 mol
m(ch3oh) = 32 g/mol
n(ch3oh) = m/m = 32 / 32 = 1 mol
n(ch3cooh) < n(ch3oh)
ch3cooh+ch3oh--> ch3cooch3+h2o
n(ch3cooh) = n(ch3cooch3) = 0.64 mol
m(ch3cooch3) = 74 g/mol
m(ch3cooch3) = n*m = 0.64*74 = 47.36 g
ответ 47.36 г
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