Ответы на вопрос:
tg20° + tg40° + tg60° +tg80° +tg100° + tg120° +tg140° + tg160° + tg180°
tg180° = 0, остается tg20° + tg40° + tg60° +tg80° +tg100° + tg120° +tg140° + tg160°
распишем tg160°, tg140°, tg120°, tg100° как tg(180°-20°), tg(180°-40°), tg(180°-60°), tg(180°-80°)
по формуле : tg(180°-α)=-tgα
tg20° + tg40° + tg60° + tg80° +tg100° + tg120° + tg140° + tg160° = tg20° + tg(180°-20°) + tg40° + tg(180°-40°) + tg60° + tg(180°-60°) + tg80° + tg(180°-80°) = tg20° - tg20° + tg40° - tg40° + tg60° - tg60° + tg80° - tg80° = 0
Tg20°+tg40°+tg60°+tg80°+tg100°+ tg120°+tg140°+tg160°+tg180°= tg20°+tg40°+√3+tg80°+tg(180°-80°)+ tg(180°-60°)+tg(180°-40°)+tg(180°-20°)+0 =tg20°+tg40°+√3+tg80°-tg80°-tg60°- tg40°-tg20°=0
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