Ответы на вопрос:
3*(3^2x) - 7*912^x) + 4*04^2x) = 0 3*(3^2x) - 7*(3^x)*(4^x) + 4*(4^2x) = 0 / (4^2x)3*[(3/4)^2x] - 7*[(3/4)^x] + 4 = 0(3/4)^x = z 3*(z^2) - 7z + 4 = 0 d = 49 - 4*3*4 = 1 z1 = (7 - 1)/6 z1 = 1 z2 = (7 +1)/6 z2 = 4/3 1) (3/4)^x = 1 (3/4)^x = (3/4)^0 x1 = 0 2) (3/4)^x = 4/3 (3/4)^x = (3/4)^(-1) x2 = -1
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