Ответы на вопрос:
X^2=6-x x^2+x-6=0 d=1+24=25 x1=(-1+5)/2=4/2=2 x2=(-1-5)/2=-6/2=-3 (-3; 2)∫(x^2+x-6)dx = x^3/3 +x^2/2 -6x | (-3; 2) = (2^3/3+2^2/2-6*2) - ( (-3)^3/3 +(-3)^2/2- -6*(-3) )= 8/3+2-12+9-9/2-18 = 2,5 = 2 2/3 -19-4,5 = 2 2/3 -23 1/2 = 2 4/6 - 23 3/6 = =20 5/6
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