Ответы на вопрос:
X^3-8x^2+20x-16 = 0 (если равно 0)преобразуем x^3-4x^2-4x^2+16x+4x-16 = 0x^2(x-4) - 4x(x-4) + 4(x-4) = 0(x-4)(x^2-4x+4) = 0(x-4)(x-2)^2=0x=2x=4
Z1 + z2 = 3 + 2i + 5 + 3i = 8 + 5i z1 - z2 = 3 + 2i - 5 - 3i = -2 - i z1*z2 = (3 + 2i)*(5 + 3i) = 15 + 9i + 10i + 6i² = 9 + 19i z1/z2 = (3 + 2i)/(5 + 3i) = [(3 + 2i)*(5 - 3i)] / [(5 + 3i)*(5 - 3i)] = =[15 - 9i + 10i - 6i²] / [25 -9i²] = (21 +i) / 34 = 21/34 + i/34
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