Ответы на вопрос:
4sin²x - 2,5sin2x + 6cos²x = 34sin²x - 2,5sin2x + 4cos²x + 2cos²x = 3 -2,5sin2x + 2cos²x = 2 -2,5sin2x + 1 + cos2x = 2 -2,5sin2x + cos2x = 1 2cos2x - 5cos2x = 2 2/√29 cos2x - 5/√29 cos2x = 2/√29 sin(γ - 2x) = 2/√29 sin(arcsin(2/√29) - 2x) = 2/√29 arcsin(2/√29) - 2x = (-1)^n arcsin(2/√29) + πn, n ∈ z - 2x = (-1)^n arcsin(2/√29) - arcsin(2/√29) + πn, n ∈ z x = )^n arcsin(2/√29)/2 + arcsin(2/√29)/2 + πn/2, n ∈ z
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