Ответы на вопрос:
1)mr(hbr) = ar(h) + ar(br) = 1 + 80 = 81 w(h/hbr) = ar(h)/ mr(hbr) x 100% = 1/81 х 100 = 1,23% w (br/hbr) = ar(br)/ mr(hbr) x 100% = 80/81 х 100 = 98,77% 2) mr(k2co3) = 2ar(k) + ar(c) + 3ar(o) = 2x39 + 12 + 3x16 = 138 w (2k/k2co3) = 2ar(k)/ mr(k2co3) x 100% = 78/138 х 100 = 56,52% w (c/k2co3) = ar(c)/ mr(k2co3) x 100% = 12/138 х 100 = 8,69% w (3о/ k2co3) = 3ar(о)/ mr(k2co3) x 100% = 48/138 х 100= 34,79%3)mr(mg(oh)2) = 24 + 16x2 + 1x2 = 58 w (mg/mg(oh)2) = 24/ 58 х 100 = 41,38%w (2o/mg(oh)2) = 32/ 58 х 100 = 55,17% w (2h/mg(oh)2) = 2/ 58 х 100 = 3,45%4)mr(p2o5) = 2x31 + 5x16 = 142 w (2p/p2o5) = 2x31/ 142 х 100 = 43,66% w (5o/p2o5) = 5x16/ 142 х 100 = 56,34% 5)mr(fecl3) = 56 + 3 x 35,5 = 162,5 w (fe/fecl3) = 56/ 162,5 х 100 = 34,46% w (3cl/fecl3) = 3x35,5/ 162,5 х 100 = 65,54% 6)mr(cu(no3)2) = 64 + 2x14 + 6x16 = 188 w (cu/cu(no3)2) = 64/ 188 х 100 = 34,04% w (2n/ cu(no3)2) = 2x14/ 188 х 100 = 14,9% w (6o/cu(no3)2) = 96/ 188 х 100 = 51,06%
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