Ответы на вопрос:
begin
var a : = new integer[5, 5](
(2, 4, 5, 1, 3),
(7, 2, 9, 0, 2),
(6, 4, 1, 0, 1),
(8, 4, 7, 2, 0),
(6, 0, 0, 2, 1));
println('массив a');
a.println(2);
println('массив b');
var b : = new integer[5, 5](
(2, 4, 5, 0, 3),
(6, 0, 3, 2, 1),
(2, 4, 5, 1, 3),
(8, 4, 7, 2, 0),
(6, 2, 0, 2, 1));
b.println(2);
println('массив a');
var c : = new integer[5, 5];
var (upper, lower) : = (0, a.rowcount - 1);
for var i : = 0 to a.rowcount - 1 do
begin
var found : = false;
for var j : = 0 to b.rowcount - 1 do
if a.row(i).sequenceequal(b.row(j)) then
begin
c.setrow(upper, a.row(i));
upper += 1;
found : = true;
break
end;
if not found then
begin
c.setrow(lower, a.row(i));
lower -= 1;
end
end;
a : = copy(c);
c : = nil; // удаляем с
a.println(2)
end.
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