Ответы на вопрос:
1)y=tg^2(x/2) 2 tg(x/2)d/dx [tg(x/2)] 2 tg(x/2)(sec^2 (u2) d/dx [x/2]) 2 tg(x/2)sec^2(x/2) d/dx [x/2] 2 tg(x/2)sec^2(x/2)(1/2 d/dx [x/1]) tg(x/2)sec^2(x/2) d/dx [x] tg(x/2)sec^2(x/2)*1 tg(x/2)sec^2(x/2) sec^2(x/2)tg(x/2)
5х-4+2(х-4)=2(-3-х)-5 -5х-4+2х-8=-6-2х-5 -5х+2х+2х=-6-5+4+8 -1х=1 х=-1 ответ: х=-1
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