Ответы на вопрос:
√3 *sin 3x = cos 3x + 1 √3 *sin 3x - cos 3x = 1 | /2 cos π/6 * sin 3x - sin π/6 * cos 3x = 1/2 sin (3x - π/6) = 1/2 1) 3x - π/6 = π/6 + 2πn 3x = π/3 + 2πn 2) 3x - π/6 = 5π/6 + 2πk 3x = 5π/6 + π/6 + 2πk 3x = π + 2πk ответ: ; ; n,k∈z
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