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esaloverzhan
07.07.2022 23:55
Математика
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Розв'яжіть рівняння х4-х2-12 =0 х+2

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milenaborowik
milenaborowik
4,8(58 оценок)
(х^4-х²-12)/(х+2)=0 х+2≠0 х≠ -2 х^4-х²-12=0 х²=t t²-t-12=0 t1+t2=1 t1t2= -12 t1=4 t2= -3 х²=t x²=4 x=±2; ( -2 не подходит по одз) х²= -3(нет решения т.к. корень из х всегда положительное число) ответ: х=2
Evgenia111111111111
Evgenia111111111111
4,5(51 оценок)

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