Решить пример 1)1+sin2h/cos2h=tg(pi/4+h) 2)cos^2 0,7x - sin^2 0,7x/4sin 0,35x*cos 0.35x*cos 0,7x
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Ответы на вопрос:
1(1+sin2h)/cos2h=tg(pi/4+h) (1+sin2h)/cos2h=(cosh²+sin²h+2sinhcosh)/(cos²h-sin²h)= =(cosh+sinh)²/(cosh-sinh)(cosh+sinh)= (cosh+sinh)/(cosh-sinh)tg(π/4+h)=sin(π/4+h)cos(π/4+h)=(sinπ/4cosh+cosπ/4sinh)/(cosπ/4cosh-sinπ/4sinh)=√2/2(cosh+sinh)/√2/2(cosh-sinh)= (cosh+sinh)/(cosh-sinh)(cosh+sinh)/(cosh-sinh)= (cosh+sinh)/(cosh-sinh)
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