Ответы на вопрос:
F'(x) = 6x²+6x-36 6x²+6x-36 = 0 ÷6 x²+x-6 = 0 d = 1+4*6 = 1+24 = 25 x1 = (-1-5)/2 = -6/2 = -3 x2 = (-1+5)/2 = 4/2 = 2 f(-3) = 2*(-3)³+3*(-3)²-36*(-3) = -54+27+108 = 81 f(2) = 2*2³+3*2²-36*2 = 16+12-72 = -44 f(-4) = 2*(-4)³+3*(-4)²-36*(-4) = -128+48+144 = 64 f(3) = 2*3³+3*3²-36*3 = 54+27-108 = -27 наибольшее: f(x) = 81 при x = -3 наименьшее: f(x) = -44 при x = 2
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