Докажите тождество (7 х - 3 ) (4-8х ) +2х( 28х - 26 ) = -12 (1.1x^2)(x^2)-10)-x(1.1x^3-9x)= -2x^2 ( -y^3 + 5y ) 2y - 10y^2 (1+0.2y^2)= - 4y^4 (2.5a + b^2 ) (-4a) + 2a(5a-b^2)=-6ab^2
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Ответы на вопрос:
1.28х- 56х²-12+24x+56x²-52x=-12 2. непонятно 3. -2y^4+10y²-10y²-2y^4=-2y^4-2y^4=4y^4 4. -10a²-4ab²+10a²-2ab²=-4ab²-2ab²=-6ab²
1) (7x-3)(4-8x)+2x(28x-26)=-12 28x-12-56x^2+24x +56x^2-52x=-12 -12=-12 2) 1,1x^2(x^2-10)- x(1,1x^3-9x)=-2x^2 1,1x^4-11x^2-1,1x^4+9x^2=-2x^2 -2x^2= -2x^2 3) (-y^3+5y)2y-10y^2(1+0,2y^2)=-4y^4 -2y^4+10y^2-10y^2-2y^4=-4y^4 -4y^4=-4y^4 4) (2.5a + b^2 ) (-4a) + 2a(5a-b^2)=-6ab^2 -10a^2-4ab^2+10a^2-2ab^2=-6ab^2 -6ab^2=-6ab^2
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