Ответы на вопрос:
4x^2 - 8x < = 5 4x^2 - 8x - 5 < = 0 4x^2 - 8x - 5 = 0 d = 64+80=144 = 12^2 x1 = (8+12)/8 = 2,5 x2 = (8-12)/8 = -1/2 2x^2 + x + x + 1 > = 3 2x^2 + 2x - 2 > = 0 x^2 + x - 1 > = 0 d = 1 + 4 = 5 x1 = (-1 + sqrt5)/2 x2 = (-1 - sqrt5)/2
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