Нужно перевести cout/cin в printf/scanf - c++ #include #include using namespace std; int main() { float a_1, a_2, a_3, x; cout < < "vvod a_1, a_2, a_3" < < endl; cin > > a_1 > > a_2 > > a_3; cout < < "proizved " < < a_1a_2a_3 < < endl; cout < < "sred geometr" < < pow (a_1a_2a_3, 1./3) < < endl; cout < < "vvod x" < < endl; cin > > x; cout < < "po form: " < < exp(1/(3(3xx-pow(pow(x+1,4) +log((pow(x,4)+4)/(pow(x,2)+ 1./5)) < < endl; int a; cout < < "vvod a" < < endl; cin > > a; int c=a%1010+a/10; cout < < c < < endl; system ("pause"); }

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lemenchuk2001

Информатика

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#include < stdio.h> #include < math.h> #include < stdlib.h> int main() { float a_1, a_2, a_3, x; printf ("vvod a_1, a_2, a_3\n"); scanf ("%f %f %f",& a_1,& a_2,& a_3); printf ("proizved = %f\n",a_1*a_2*a_3); printf ("sred geometr = %f\n",pow(a_1*a_2*a_3, 1.0/3)); printf ("vvod x\n"); scanf ("%f",& x); printf ("po form: %f\n",exp(1.0/(3*(3*x*x-pow(pow(x+1,4)+log((pow(x,4)+4)/(pow(x,2)+.0/; int a; printf ("vvod a\n"); scanf ("%d",& a); int c=a%10*10+a/10; printf ("%d",c); system ("pause"); } пример: vvod a_1, a_2, a_32 3 5proizved = 30.000000sred geometr = 3.107233vvod x4po form: -42.913096vvod a7117