Ответы на вопрос:
A) 3a(a+1)+(a+2)(a-3) = = 3a^2+3a+ a^2-3a+2a-6 = = 4a^2 + 2a - 6 b) (y-3)(5--y)(y+6) = = (5y-y^2-15++24-y^2-6y)= = 5y - y^2 -15 + 3y - 4y - 24 + y^2 +6y = = 10y - 39
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