25 . выражение (1+8y^3/1-2y+4y^2 + 8-y^3/4y+2y^2+y^3): (8+y^3/4y-2y^2+y^3 - 1-8y^3/1+2y+4y^2)
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Ответы на вопрос:
1)(1+2y)(1-2y+4y²)/(1-2y+4y²)+(2-y)(4+2y+y²)/[y((4+2y+y²)]= =(1+2y)+(2-y)/y=(y+2y²+2-y)/y=(2y²+2)/4=2(y²+1)/y 2)(2+y)(4-2y+y²)/[y(4-2y+y²)]-(1-2y)(1+2y+4y²)/(1+2y+4y²)= =(2+y)/y-(1-2y)=(2+y-y+2y²)/y=(2+2y²)/y=2(1+y²)/y 3)2(y²1)/y: 2(1+y²)/y=1
X^4-17x^2+16 = 0 t^2-17t+16 = 0 t= 16 t = 1 x^2 = 16 x^2 = 1 x = 4 x = –4 x = 1 x = –1
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