Ответы на вопрос:
5π/3 = π + 2π/3 13π/6 = 2π + π/6 7π/6 = π+ π/6 подставим эти замены ctg (5π/3) *cos(13π/6)*sin(7π/6) = ctg (π + 2π/3)*cos(2π + π/6)*sin(π+ π/6)= = -ctg (2π/3)*cos(π/6)*(-sin(π/6)) = 1/2* ctg (2π/3)*2cos(π/6)*sin(π/6)= =1/2ctg (2π/3)*sin(π/3)=1/2 * 1/√3* √3/2 = 1/4=0,25
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