Ответы на вопрос:
2^(x^2-1) - 3^(x^2) = 3^(x^2-1) - 2^(x^2+2)2^(x^2-1) - 3^(x^2) - 3^(x^2-1) + 2^(x^2+2) = 0 /: 3^x^2 (2/3)^(x^2)*1/2 - 1 - 1*1/3 + (2/3)^(x^2)*4 = 0 (2/3)^(x^2)*1/2 - 4/3 + (2/3)^(x^2)*4= 0 (2/3)^(x^2)*1/2 + (2/3)^(x^2)*4 = 4/3 (2/3)^(x^2)*(1/2 + 4) = 4/3 (2/3)^(x^2)*(9/2) = 4/3 (2/3)^(x^2) = 8/27 (2/3)^(x^2) = (2/3)^3 x^2 = 3 x = ± √3 ответ - √3; √3
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