Ответы на вопрос:
3(2х² + 5х)² - (2х² + 5х + 1)² = 23пусть 2х² + 5х = t 3t^2 - (t + 1)^2 = 23 3t^2 - (t^2 + 2t + 1) - 23 = 0 3t^2 - t^2 - 2t - 1 - 23 = 0 2t^2 - 2t - 24 = 0 /: 2 t^2 - t - 12 = 0 d = 1 + 48 = 49 t1 = ( 1 + 7)/2 = 8/2 = 4; t2 = ( 1 - 7)/2 = - 6/2 = - 3 обратная замена 2х² + 5х = 4 2х² + 5х - 4 = 0 d = 25 + 32 = 57 x₁ = ( - 5 + √57)/4 x₂ = ( - 5 - √57)/4 2x² + 5x = - 3 2x² + 5x + 3 = 0 d = 25 - 24 = 1 x₃ = ( - 5 + 1)/4 = - 4/4 = - 1 x₄ = ( - 5 - 1)/4 = - 6/4 = - 1,5
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