Ответы на вопрос:
F(x)=2x³-12x²+18x+3; [-1; 2] f⁾(x)=6x²-24x+18 x²-4x+3=0 d=4 x=-3; x=-1 -1∈[-1; 2]; -3∉[-1; 2] f(-1)=-2-12-18+3=-29 f(2)=16-48+36+3=7 max f(x)=f(2)=7 min f(x)=f(-1)=-29
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