Ответы на вопрос:
X^3-y^3+5x(x^2+xy+y^2)=(x-y)(x^2+xy+y^2)+5x(x^2+xy+y^2)= =(x^2+xy+y^2)(x-y+5x)=(x^2+xy+y^2)(6x-y). и не )
25-(13+ t)² = 0; 25-(169+26t+t²) = 0; 25-169-26t-t² = 0; -t²-26t-144 = 0; d = b²-4ac = 676-4*(-1)*(-144) = 100. t1 = -b+√d/2a = 26+10/(-2) = 36/(-2) = -18; t2 = -b-√d/2a = 26-10/(-2) = 16/(-2) = -8. ответ: t1 = -18; t2 = -8.
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