Ответы на вопрос:
((x+2)^2/-4)/-2)^2/8)=x^2/8, (4(x+2)^2/(x^2-4)/-2)^2//8)=0, (4(x^2+4x+4)-2(x^2--4x+4)-x^2)/8=0 (4x^2+16x+16-2x^2+8-x^2+4x-4-x^2)/8=0, (20x+20)/8=0, 20x+20=0, x=-1.
1) 3х-у=3,-у=3-3х, у=-3+3х, 3х-2(-3+3х)=0, -3х+6=0, -3х=-6, х=-6: (-3)=2, у=-3+3*2=3, х=2,у=3. 3). 2х+у=1, у=1-2х, 5х+2(1-2х)=0, 5х+2-4х=0, х+2=0,х=-2,у=1-2*(-2)=5,х=-2,у=5 . 4) 2х-3у=1,3х+у=7, у=7-3х, 2х-3(7-3х)=1, 2х-21+9х=1,11х=22,х=22: 11, х=2, у=7-3*2,у=1. 5)х+у=6, 5х-2у=9, х=6-у, 5(6-у)-2у=9, 30-7у=9, -7у=9-30, у=-21: (-7),у=3, х=6-3, х=3
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