Ответы на вопрос:
1) y' = ((2 - x^2/4)^3)' = 3(2 - x^2/4)^2*(2 - x^2/4)' = = 3(2 - x^2/4)^2*( - 2x/4) = - 1,5x (2 - x^2/4)^2 2) sin (3x + pi/4) = 1 3x + pi/4 = pi/2 + 2pik 3x = pi/2 - pi/4 + 2pik 3x = 2pi/4 - pi/4 + 2pik 3x = pi/4 + 2pik x = pi/12 + (2pik)/3, k ∈ z
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