Ответы на вопрос:
Cos(x )-cos(y) = -2·sin(½(x+y))·sin(½(x-y))cos 3x - cos x = -2 sin (3x+x)/2 * sin (3x-x)/2 = -2sin 2x * sinxsin x (1+2sin 2x)=0sinx=0x= πn n⊂z 2sin2x=-1sin2x=-1/22x= (-1)ⁿ (-π/6) + πk k ⊂ z x= (-1)ⁿ (-π/12) + πk/2 k⊂z
Решение 1) 4tg²x-9=0 4tg²x = 9 tg²x = 9/4 a) tgx = -3/2 x1 = - arctg(3/2) + πn, n∈z tgx = 3/2 b) tgx = 3/2 x2 = arctg(3/2) + πk, k∈z ответ: x1 = - arctg(3/2) + πn, n∈z; x2 = arctg(3/2) + πk, k∈z 2) 3tg²x-2tgx=0 tgx * (3tgx - 2) = 0 tgx = 0 x1 = πk, k∈z 3tgx - 2 = 0 tgx = 2/3 x2 = arctg(3/2) + πn, n∈z ответ: x1 = πk, k∈z: x2 = arctg(3/2) + πn, n∈z
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