Ответы на вопрос:
A) √3ctg(x/2) = 3 ctg(x/2) = 3/√3 ctg(x/2) = √3 x/2 = π/6 + πk, k€z x = π/12 + πk/2, k€z. b) sin(π/6 - 2x) = 0 -sin(2x - π/6) = 0 sin(2x - π/6) = 0 -π/6 + 2x = πk, k€z 2x = π/6 + πk, k€z x = π/12 + πk/2, k€z.
Популярно: Алгебра
-
mariaks1608.06.2021 13:16
-
KopolbEnufaHtuy12.12.2022 00:14
-
ZzzGoshAzzZ09.12.2020 00:59
-
saraarakelyan129.05.2023 02:14
-
kimiKatocom16.07.2020 21:34
-
adelinanurgazi30.12.2021 19:06
-
nicekuzia0118.11.2020 18:07
-
Mysteryon09.09.2020 20:09
-
8928070422821.08.2021 14:55
-
osheefit27.07.2021 22:48