Ответы на вопрос:
А) sin2x = 1/2 2x = (-1)^k * π/6 + πk, k∈z x = (-1)^k * π/12 + πk/2, k∈z б) 1 + 2cosx = 0 2cosx = -1 cosx = -1/2 x = +/- 2π/3 + 2πk, k∈z
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