Ответы на вопрос:
2) -5*0,8с-5*(-0,9d) -4с+4,5d 4) 7m*m-7mn-7mp 7m^2-7mn-7mp 6) (-5/12)*4x-(5/12)*6y-(5/12)*3 (-5/3)x-(5/2)y-(5/4)
2cos4x - 4cos2x + 3 = 0 2(2cos²2x - 1) - 4cos2x + 3 = 0 4cos²2x - 4cos2x + 1 = 0 cos2x = t 4t² - 4t + 1 = 0 d = 16 - 16 = 0 t = 4/8 = 1/2 cos2x = 1/2 2x = π/3 + 2πn или 2x = - π/3 + 2πk x = π/6 + πn x = - π/6 + πk отрезку принадлежат корни: π/6 и - π/6
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