Ответы на вопрос:
sin2x + cos2x = 1
tgx = sinxcosx ctgx = cosxsinxtgx ctgx = 1
tg2x + 1 = 1cos2x ctg2x + 1 = 1sin2xформулы двойного аргументаsin2x = 2sinx cosx
sin2x = 2tgx = 2ctgx = 21 + tg2x1 + ctg2xtgx + ctgxcos2x = cos2x - sin2x = 2cos2x - 1 = 1 - 2sin2x
cos2x = 1 - tg2x = ctg2x - 1 = ctgx - tgx1 + tg2xctg2x + 1ctgx + tgx tg2x = 2tgx = 2ctgx = 21 - tg2xctg2x - 1ctgx - tgx ctg2x = ctg2x - 1 = ctgx - tgx2ctgx2Популярно: Алгебра
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